Given two integers M & N, calculate and return their multiplication using recursion. You can only use subtraction and addition for your calculation. No other operators are allowed.

PROBLEM:-

Multiplication (Recursive)

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Given two integers M & N, calculate and return their multiplication using recursion. You can only use subtraction and addition for your calculation. No other operators are allowed.

Input format :

Line 1 : Integer M
Line 2 : Integer N

Output format :

M x N

Constraints :

0 <= M <= 1000
0 <= N <= 1000

Sample Input 1 :

3 
5

Sample Output 1 :

15

Sample Input 2 :

4 
0

Sample Output 2 :

0

SOLUTION:-

#include <iostream>
using namespace std;

int multiplyNumbers(int m, int n) {
    // Write your code here
    if(n==0)
        return 0;
    return m+multiplyNumbers(m,n-1);

}

int main() {
    int m, n;
    cin >> m >> n;
    cout << multiplyNumbers(m, n) << endl;
}




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